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Now append an else clause that has sortByLosses() return -1 if the Pirates lost more games in e1 than e2, and 1 if the Pirates lost more games in e2 than e1: var pirates = [[2010, 57, 105], [2009, 62, 99], [2008, 67, 95], [2007, 68, 94], [2006, 67, 95], [2005, 67, 95], [2004, 72, 89], [2003, 75, 87], [2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83], [1998, 69, 93], [1997, 79, 83], [1996, 73, 89], [1995, 58, 86], [1994, 53, 61], [1993, 75, 87]]; var sortByLosses = function (e1, e2) { if (e1[2] === e2[2]) { return e1[0] > e2[0] -1 : 1; } else { return e1[2] > e2[2] -1 : 1; } }; OK, time to see if sortByLosses() does what we want it to. So invoke sort() on pirates and pass the sortByLosses identifier don t invoke sortByLosses with the () operator or you'll come to grief. sort() will then reorder and return pirates. So if we invoke console.dir() on the return value of sort(), JavaScript will print the reordered array in Firebug as Figure 6 33 displays. var pirates = [[2010, 57, 105], [2009, 62, 99], [2008, 67, 95], [2007, 68, 94], [2006, 67, 95], [2005, 67, 95], [2004, 72, 89], [2003, 75, 87], [2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83], [1998, 69, 93], [1997, 79, 83], [1996, 73, 89], [1995, 58, 86], [1994, 53, 61], [1993, 75, 87]]; var sortByLosses = function (e1, e2) { if (e1[2] === e2[2]) { return e1[0] > e2[0] -1 : 1;

The code creates a new Person object and sets its primary key to the value of the row we are going to remove. Finally, the object is passed to the Remove method and the changes are submitted with the SubmitChanges() method call.

} else { return e1[2] > e2[2] -1 : 1; } }; console.dir(pirates.sort(sortByLosses));

Figure 4 2. DemoBot making a 180-degree turn with a single motor would create a steering circle with the diameter being twice that of the robot s track. The track is the distance between the robot s drive wheels. The center of the steering circle would be the point at which the robot would pivot on the nonmoving wheel.

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We ve focused our attention on the basic features provided by LINQ to SQL (in the System.Data.DLinq.dll assembly). Data contexts have even more features. In the next sections you ll see how to define relationships between entities, and the benefits of doing that.

Figure 6 33. Sorting elements in the pirates array by losses and then by year Forgive me for being negative and sorting by losses. In Pittsburgh, between the end of the Penguins season and beginning of the Steelers season, guessing how many games the Pirates will lose and which star players they ll trade away for prospects is pretty much all there is to do sports-wise. So let s be optimistic and sort pirates by wins instead. Doing so is trivial, just rename the function sortByWins and change the indexes in the boolean expression and else clause from 2 to 1 like so. var pirates = [[2010, 57, 105], [2009, 62, 99], [2008, 67, 95], [2007, 68, 94], [2006, 67, 95], [2005, 67, 95], [2004, 72, 89], [2003, 75, 87], [2002, 72, 89], [2001, 62, 100], [2000, 69, 93], [1999, 78, 83], [1998, 69, 93],

With the single-wheel turn, our robot is only powering one wheel and turns the robot around an arc. But if we turn both wheels in opposite directions, we can pivot the robot right where it is sitting. The pivot point is no longer the stationary wheel but the center of the robot s track. We can even calculate the number of degrees needed to make the turn in the same way that we did with the single-wheel turn. The only difference is that we will have to divide the degrees in half and apply them to both wheels and remember that one wheel will be going in the opposite direction of the other. In Figure 4 3, you can see that the steering circle is much smaller than the steering circle of a single wheel turn, actually half the size.

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